(4+x)^2=(4+x)(17x+2)

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Solution for (4+x)^2=(4+x)(17x+2) equation: 



(4+x)^2=(4+x)(17x+2)

We move all terms to the left:

(4+x)^2-((4+x)(17x+2))=0

We add all the numbers together, and all the variables

(x+4)^2-((x+4)(17x+2))=0

We multiply parentheses ..

-((+17x^2+2x+68x+8))+(x+4)^2=0



We calculate terms in parentheses: -((+17x^2+2x+68x+8)), so:

(+17x^2+2x+68x+8)

We get rid of parentheses

17x^2+2x+68x+8

We add all the numbers together, and all the variables

17x^2+70x+8

Back to the equation:

-(17x^2+70x+8)



We get rid of parentheses

-17x^2-70x+(x+4)^2-8=0

We move all terms containing x to the left, all other terms to the right

-17x^2-70x+(x+4)^2=8

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